Question

Two equal circles, O and Q of radius 8 intersect at X and Y. If OQ is 12, find the length of the common chord XY.

Answer 1

let R be the intersection of OQ and XY
R is midpoint of XY
XQ = 8, RQ = 1/2 * 12 = 6
use pythagoras to Find length of XR
XY = 2 XR

Answer 2

do you follow kmeds?

Answer 3

use right triangle properties.

Answer 4

XY and OQ are perpendicular.

Answer 5

@cwrw238 \[8\sqrt{3}\] ?

O_-

Answer 6

No...it's close...

Answer 7

oh no, hahaha. 64-36 lol

Answer 8

RQ^2 = 8^2 - 6^2 = 64-36 = 28

Answer 9

4\sqrt{7}?\]

Answer 10

\[4\sqrt{7}\] ?

Answer 11

\[ XY=4\sqrt{7}\] if you got it correctly.

Answer 12

yea

Answer 13

i was thinking 4. lol so i did, 64-16. hahahaha xD
thank you @NewbieCarrot & @cwrw238 !