Question

Calculating phase shift of cos function?
h(t)= a cos b (x + c) + d
a= 0.60
b=200π/1233
c=?
d= 1.30

Answer 1

What I have done so far:
h(t)= a cos b (t + c) +d
1.96= 0.60 cos 200π/1233 (0 + c ) + 1.30
1.96= 0.60 cos ( 200π/1233 x 0 ) + ( 200π/1233 x c) +1.30
1.96= 0.60 cos 0 + 200π/1233 c + 1.30
0.66= 0.60 cos 200π/1233 c
1.1= cos 200π/1233 c
〖cos〗^(-1) 1.1= θ θ=200π/1233
〖cos〗^(-1) 1.1= 200π/1233

Answer 2

But I can't do inverse cos of 1.1, it's not real in calc! So what do I do!

Answer 3

how did u get h(t) = 1.96 ?

Answer 4

Oh I picked a point on the curve h=1.96 t=0

Answer 5

1.96= 0.60 cos 200π/1233 (0 + c ) + 1.30
1.96= 0.60 cos( 200π/1233c) + 1.30

Answer 6

oh yeah, even i m getting 1.1

Answer 7

sure, your h(t) is correct ?

Answer 8

oh, waits , is it
h(t)= a cos [b (x + c) + d]??

Answer 9

I'm pretty sure it's just h(t)=a cos b (x + c) +d

Answer 10

max value of h(t) must be a+d = 1.9
it can't be 1.96

Answer 11

because max value of cos is 1

Answer 12

a+d?

Answer 13

Yeah well the thing is, this is a function i have to develop based on real data on tides. So every height of each tide is different so we have to average it.