Question

The first term of geometric progression is two thirds of the sum to infinity. Find the common ratio.

Answer 1

1st term = a
sum to infinity = a/(1-r)
r = common ratio
Given :
a= (2/3) a/(1-r)
can u find r from here ?

Answer 2

\[S \infty = \frac{ a }{ 1-r }\]

Answer 3

Could u please help me further?

Answer 4

a= (2/3) a/(1-r)
cancelling a.
1 = 2/3 /(1-r)
1-r = 2/3
r = 1-2/3 = ??

Answer 5

r=1/3