Mathematics
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OpenStudy (anonymous):
A certain function f has the property that f(x+y)=
f(x)+f(y) for all values of x and y. Which of the
following statements must be true when a=b?
I. f(a+b)=2f(a).
II. f(a+b)=[f(a] to the power of 2.
III. f(b) +f(b)=f(2a)
13 years ago
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OpenStudy (anonymous):
this is a function problem...
13 years ago
OpenStudy (cruffo):
(i) is true
f(a+b) = f(a) + f(b) = f(a) + f(a) = 2f(a)
13 years ago
OpenStudy (anonymous):
f(a+b) = f(a+a) = f(a) + f(a) = 2f(a)
13 years ago
OpenStudy (anonymous):
ahh, since a=b, right?
13 years ago
OpenStudy (anonymous):
I. f(a+b)=2f(a) is true because f(a+b) = f(a) + f(b), since a = b, f(b) = f(a), so f(a) + f(a) = 2f(a) so I must be true.
13 years ago
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OpenStudy (anonymous):
all good responses
13 years ago
OpenStudy (cruffo):
(iii) is also true. Just use what is given.
13 years ago
OpenStudy (anonymous):
let us see
13 years ago
OpenStudy (anonymous):
II. isn't true
13 years ago
OpenStudy (anonymous):
And because of this, II is false.
13 years ago
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OpenStudy (anonymous):
a=1, b=1
13 years ago
OpenStudy (anonymous):
wait
13 years ago
OpenStudy (anonymous):
a=3
13 years ago
OpenStudy (anonymous):
b=3
13 years ago
OpenStudy (anonymous):
6 does not equal 9
13 years ago
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OpenStudy (anonymous):
but f(2a)
13 years ago
OpenStudy (anonymous):
because
13 years ago
OpenStudy (anonymous):
f(b)+f(b)=f(2b)=f(2a)
13 years ago
OpenStudy (anonymous):
right?
13 years ago
OpenStudy (anonymous):
Yeah.
13 years ago
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OpenStudy (anonymous):
ty micah
13 years ago
OpenStudy (cruffo):
f(b)+f(b)=f(2b)=f(2a) is a good statement.
I'm not sure why you are using #'s like 1 and 3
13 years ago
OpenStudy (anonymous):
sometimes I like to pick variables to solve the problem...
13 years ago
OpenStudy (cruffo):
Usually, that's a good strategy, but you don't know what f(x) is in this case.
13 years ago
OpenStudy (anonymous):
We don't know function so you can't use number as a variable. We only know that f(a + b) = f(a)+ f(b), that all.
13 years ago
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OpenStudy (anonymous):
Just like cruffo said.
13 years ago
OpenStudy (anonymous):
ty, guys
13 years ago
OpenStudy (anonymous):
next problem?
13 years ago
OpenStudy (anonymous):
ok
13 years ago
OpenStudy (anonymous):
Ask as many questions as you like.
13 years ago
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OpenStudy (anonymous):
ty
13 years ago