Prove this identity sin(2A)=2sinAcosA.
Start by considering 2A as A+A ... does that make you think of any particular theorem?
...of course that makes me want to know how to prove the theorem you are thinking of @Tonks
sin(a+a)=sinacosb+cosasinb put the value of a and be here.
We know that sin(2A) = sin(A + A) sin (A + A) = cosA sinA + cosA sinA = 2 sinA cosA QED
@TuringTest try stacking triangles in the unit circle... or is that for cosine?
I know it was some geometric proof like that, I don't remember those darn things...
Is that enough or do you need proof for sin (A + B) = cosA sinB + cosB sinA
formula you have given is wrong @micahwood50
it's correct
For proof of sin (A + B) = cosA sinB + cosB sinA: http://en.wikipedia.org/wiki/Proofs_of_trigonometric_identities#Sine
yep, that's the one...
@muhammad9t5 It's the same. Your point is?
perhaps you are neglecting the fact that multiplication is commutative muhammad?
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