Question

Can someone help me with this equation using long division? I will post the equation shortly.

Answer 1

use a calculator

Answer 2

\[(x-2)/5x+5x+2x^3+6\]

Answer 3

I need to show work though...

Answer 4

simplify the bottom so that you end up with (x-2) in the denominator so that you can cancel the numerator with it

Answer 5

Can you draw what you did to solve it because I learn visually.

Answer 6

Sorry I don't know if that's even possible you have to try it out and see if it comes out like that.

Answer 7

I'm wondering if you posted the equation correctly - This doesn't look like a long division problem. Is the x-2 supposed to go into a polynomial? (It looks like (x-2/5x) + 5x + etc.

Answer 8

I would expect long division for a polynomial would look like this:
\[\frac{ 5x +2x^{3} +6 }{ x-1 }\]
with the polynomial on top, and the simpler term on the bottom.

Answer 9

I know right? I did it the other way and got the correct answer, but she said to use long the divison....here is the equation in my book - (5x+5x^2+2x^3+6)/(x-2). Maybe that might be a little more clear.

Answer 10

Okay, that makes more sense to me. I don't have a stylus, so you'll have to bear with me.

Answer 11

First you want to rearrange the terms of the polynomial on the bottom so they are in order from highest exponent to lowest, and set it up like a long division:

x-2 goes into 2x^3 + 5x^2 + 5x + 6

Answer 12

If you give me a few minutes, I'll write it out on paper and post a picture -- would that work?

Answer 13

Yes thank you! :)

Answer 14

Can you follow what I did?

Answer 15

theres an error on second line - should be -2*2x^2 = -4x^2

Answer 16

Oh, I see what I did! Thanks so much! AHHH!

Answer 17

so instead of 3x^2 on third line it should read (5x^2 - (-4x^2)) = 9x^2

Answer 18

Yes - thanks. cwrw is right. That affects the rest of the problem -- still there, lost&confused?

Answer 19

Yes, I got it. Thank you guys so much! I still have a been to do, but I'll come back if I need help. :)

Answer 20

Not to mention that I never subtracted -- I've been doing so many equation combining lately, and I aim for adding to eliminate the variable -- ERG!!!
Ok - so I demonstrated the method, but my math is messed up.

Answer 21

It's okay, I got it from here. :)

Answer 22

Ok, good.

Answer 23

Can you help me long divison a few other another problems?