Find Y,X. We have (2i -3)y + (2 +3i)x^2 = 2x - 3y + 15i.

So we get :
-3y + 2x^2 = 2x - 3y
2y + 3x^2 = 15

Next step will be probably modify on :

2x^2 - 2x = 0
3x^2 + 2y = 15

And that is my end. Dont know how to count with x^2 :/

Question

Find Y,X.  We have (2i -3)y + (2 +3i)x^2 = 2x - 3y + 15i.

So we get :
-3y  + 2x^2 = 2x - 3y
2y + 3x^2 = 15

Next step will be probably modify on :

2x^2 - 2x = 0
3x^2  + 2y = 15

And that is my end. Dont know how to count with x^2 :/

phi · Answer

You are very far along.  The first equation can be factored to find x

anonymous · Answer

2x^2 - 2x = 0
factor the x
2x(x-1) =0
x = 0;x = 1
sub it into the second equation to find y
3(0)^2 +2y = 15
y = 15/2
and 
3(1)^2 + 2y = 15
y = 6
so you get values (0,15/2) and (1,6)

well · Answer

Thanks a lot. It takes me a while to realize. Thanks guys !