Mathematics
7 Online
OpenStudy (anonymous):
Differentiate.
f(θ) = sec θ/3 + sec θ
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OpenStudy (anonymous):
\[f(t) = \frac{ \sec(t) }{ 3 } + \sec(t)\]
OpenStudy (anonymous):
this is the question ?
OpenStudy (anonymous):
or it's 3+sec(t) in the denominator ?
OpenStudy (anonymous):
yeaaa
OpenStudy (anonymous):
in the denominator
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OpenStudy (anonymous):
\[f(t)=\frac{ \sec(t) }{ 3 + \sec(t) }\]
OpenStudy (anonymous):
like this ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
In this case, use quotient rule.
OpenStudy (anonymous):
grr mistake :| all over again
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OpenStudy (anonymous):
\[f'(t) = \frac{ \sec(t)' * (3+\sec(t)) - (3+\sec(t))' * \sec(t) }{ (3+\sec(t))^2 }\]
OpenStudy (anonymous):
\[f'(t) = \frac{ \tan(t)\sec(t) * (3+\sec(t)) - \tan(t)\sec(t) * \sec(t) }{ (3+\sec(t))^2 }\]
OpenStudy (anonymous):
\[f'(t) = \frac{ 3\tan(t)\sec(t) }{ (3+\sec(t))^2 }\]
OpenStudy (anonymous):
nothing much more to do ..
OpenStudy (anonymous):
so you expand and simplify?
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OpenStudy (anonymous):
the final answer ? you can expand the (3+sec(t))^2 but it's not really important ..
OpenStudy (anonymous):
i used the quotient rule in order to find the derivative as you can see the procedure
OpenStudy (anonymous):
okaay thank you :)
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
i got the aanswer wrong
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OpenStudy (anonymous):
i'm doing this online quiz and wen i put in the answer it was wrong