Question

How to tell what i^33 is . I remember doing this in algebra 2 but I forgot how to

Answer 1

i^4 = 1
33 = 4x8+1
=> i^33=i^1=i

Answer 2

i^1=i
i^2=-1
i^3=-i
i^4=1

That's the pattern, so look for anay number smaller than the given or the given and check if it's divisible by 4. In this case as rahul91 wrote 4*8+1=33 so you know that i^32 equals 1 and i^1 equals i so the answer is 1*i

Answer 3

Any exponentnummber divisible by four equals 1 by the pattern above

Answer 4

Thank you @frx very helpful :)

Answer 5

np