Question

Find the limit.
lim 3 − 3 tan x/sin x − cos x
x→π/4

Answer 1

Could you write out how this looks. the division sign doesn't really indicate where the equation is divided.

Answer 2

At least put parenthesis where they belong.

Answer 3

lim (3 − 3 tan x)/(sin x − cos x)
x→π/4

Answer 4

First try to just put in the value pi/4 and decide if the function is defined in that point

Answer 5

you'll get -3sqrt(2)

Answer 6

You see that sin pi/4- cos pi/4 equals zero so the function is undefined at pi/4 so what you want to do is to simplify the function

Answer 7

okaaaaaaaaay thambi

Answer 8

how do i simplify this?

Answer 9

you can turn your denominator into\[(3-3(\frac{ cosx }{ sinx })\] then split the numerator into two different fractions\[\frac{ 3 }{ sinx-cosx } - \frac{ \frac{ sinx }{ cosx } }{ sinx-cosx }\]

Answer 10

sorry meant numerator

Answer 11

and that should have been three times sine over cosine sorry I am messing it up pretty bad

Answer 12

loll
itss okayy

Answer 13

i dont get the question

Answer 14

\[\frac{ 3-3\tan(x) }{ \sin(x) - \cos(x) } \times \frac{ \sin(x) +\cos(x) }{ \sin(x) +\cos(x) }\]

Answer 15

\[\frac{ 3\sin(x) - 3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) -3\sin(x) }{ \sin^2(x) -\cos^2(x) }\]

Answer 16

\[\frac{ - 3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) }{ \sin^2(x) -\cos^2(x) }\]

Answer 17

\[\frac{ - 3\sin^2(x) + 3\cos^2(x) }{ \cos(x)[\sin^2(x) -\cos^2(x)] } = \frac{ -3 }{ \cos(x) }\]

Answer 18

sorry i was busy

Answer 19

so i sub in pi/4

Answer 20

yes

Answer 21

-3/(1/sqroot2)

Answer 22

which simplifies into -3sqrt(2)

Answer 23

-sqroot2/3

Answer 24

no .. -3 * sqrt(2)

Answer 25

yeye

Answer 26

i gett it

Answer 27

\[-3\sqrt2\]

Answer 28

like this