For questions 3–4, what is the value of x to the nearest tenth?
3.
circle with radius X (1 point)

4.2
6.6
10.4
11.6

4.
circle (1 point)

3.6
5.8
11.5
14.3

Question

For questions 3–4, what is the value of x to the nearest tenth?
3.  
circle with radius X  (1 point)

    4.2
    6.6
    10.4
    11.6

4.  
circle  (1 point)

    3.6
    5.8
    11.5
    14.3

anonymous · Answer

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anonymous · Answer

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nubeer · Answer

4.
apply pythagoras theorem 
6.5^2 = 3^2 + y ^2
solve and get value of y which will be y = 5.76
as i have found the half of the length , so
x =2y
x =11.5

anonymous · Answer

okt thankyou!:)

nubeer · Answer

you're welcome.. u have to solve the other question by same way..

anonymous · Answer

nubeer the first question is not like the second.What about that question?

nubeer · Answer

its same.. u just have to find the hypotaneous .. which will be same as value of x

anonymous · Answer

but nubeer dear 3.6 and 11 are points.Not the magnitudes of lengths.so..?

nubeer · Answer

i dont think those are points .. those are magnitudes.. ..i dont think anywhere it states that those are maginitude.. if 11 would be a point it would also have another coordinate to find the magnitude.

anonymous · Answer

yes.I was taking them as a point and was confused that how to find the second coordinate.

anonymous · Answer

$$\sqrt{43} ans. solve \sqrt{43} by calculator i have nt dis time.$$

nubeer · Answer

well it's not point.. its magnitude bcos 11 is written clearing that its magnitude. and
@reno15  no your answer is not correct.. let me tell u again
Hyp ^2 = base ^2 + perpendicular ^2
in your 3rd question case
base = 11/2
perp = 3.6
so 
hyp^2 = 5.5^2 + 3.6^2
hyp^2 = 43.21
hyp =6.57

anonymous · Answer

hmmm.well nubeer
It's right!!!

anonymous · Answer

thanx guyz!! :D

nubeer · Answer

you're welcome :)

anonymous · Answer

Most Welcome....