f(z)= z^2+1/3z
Power and polynomial derivatives

Question

f(z)= z^2+1/3z 
Power and polynomial derivatives

anonymous · Answer

all iknw is that the derivative of $$f(z)=z^2+(1/3)z^{-1}$$ is
$$2z-(1/3)z^{-2}$$
nt sure about power and polynomial der

anonymous · Answer

the answer in the back of the book is 
(z^2-1) /3z^2 
Can you tell me the steps needed to get there I don't know the algebra :/

anonymous · Answer

well do you get the direvative answer i wrote on top

anonymous · Answer

is the question$$f(z)=z^2+\frac{ 1 }{ 3 z}$$

anonymous · Answer

i think it must be 
$$\frac{z^2+1}{3z}$$

anonymous · Answer

you have a choice, you can divide term by term and find the derivative 
my guess is that is what you are asked to do

anonymous · Answer

@satellite73 is answering the right question and youll get that answer on your txt book

anonymous · Answer

divide and get 
$$\frac{1}{3}z+\frac{1}{3z}$$ derivative of $\frac{1}{3}z$ is $\frac{1}{3}$ 
derivative of $\frac{1}{3z}$ is $-\frac{1}{3z^2}$

anonymous · Answer

algebra is 
$$\frac{1}{3}-\frac{1}{3z^2}=\frac{z^2}{3z^2}-\frac{1}{3z^2}=\frac{z^2-1}{3z^2}$$

anonymous · Answer

thanks Im reviewing all of this

anonymous · Answer

I guess I dont see how to get 1/3z + 1/3z