Help Please! Attachments to follow.
Here's what I got so far, but the answer is incorrect.
Hmm, looks like a cumbersome way to do it. Do you know L'Hopital's rule?
I've heard of it...but i don't really understand it...
You differentiate the top and bottom, then reevaluate, it can get rid of indeterminate forms.
i'm not really sure how to do that...could you please show me?
Do you know what the derivative of cosine is?
yes. but i don't think i'm supposed to be using derivatives to find the limit...is there a way to just find the limit without using derivatives?
The hint given shows how to make a substitution to get it in terms of sine, and it looks like you did that correctly, but what is the value of a?
I was hoping you could tell me...
:-) Let's look at the substitution made cos(7x) = a*sin(x-3π/2) Why do you suppose that works?
it could be derived from some trig identities that i'm unaware, possibly something like the double angle theorem?
*(oops, meant cos(7x) = a*sin(7(x-3π/2)) as the substitution) Yes, it has to do that sine and cosine differ by 90º
So am i supposed to solve for a first?
Yes. Pick some other value of x and compare cos(7x) with sin(7(x-3π/2)).
I set x = 1 and both cos(7x) and sin(7(x-3π/2)) came out the same...doesn't that imply that a = 1?
Are you sure they were exactly the same?
Oh! Whoops i must have typed it into my calculator wrong! They are opposites...so does that mean that a=-1?
Yes. :-)
So what's the limit?
The limit is -7!
You got it!
Thanks so much for your help! :D
Do some more research on L'Hopital's rule and try this problem using that method. I think you'll like it.
Is there any good resources that you'd recommend for it?
Wikipedia has a good article, but it might be a little too dense. Try maybe Paul's Online Math Notes http://tutorial.math.lamar.edu/Classes/CalcI/LHospitalsRule.aspx It's the go-to place for most good notes and examples.
I'll show you how it works on the problem you had here: \[\large \lim_{x \rightarrow 3π/2} \frac{cos(7x)}{x-3π/2} = \lim_{x \rightarrow 3π/2} \frac{\frac{d}{dx}cos(7x)}{\frac{d}{dx}(x-3π/2)}\] \[\large \rightarrow \lim_{x \rightarrow 3π/2} \frac{-7sin(7x)}{1} = -7.\]
Better, eh?
Yeah much better! I will check out that site for sure! Thanks again! :D
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