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Mathematics 8 Online
OpenStudy (poofypenguin):

Help Please! Attachments to follow.

OpenStudy (poofypenguin):

OpenStudy (poofypenguin):

Here's what I got so far, but the answer is incorrect.

OpenStudy (anonymous):

Hmm, looks like a cumbersome way to do it. Do you know L'Hopital's rule?

OpenStudy (poofypenguin):

I've heard of it...but i don't really understand it...

OpenStudy (anonymous):

You differentiate the top and bottom, then reevaluate, it can get rid of indeterminate forms.

OpenStudy (poofypenguin):

i'm not really sure how to do that...could you please show me?

OpenStudy (anonymous):

Do you know what the derivative of cosine is?

OpenStudy (poofypenguin):

yes. but i don't think i'm supposed to be using derivatives to find the limit...is there a way to just find the limit without using derivatives?

OpenStudy (anonymous):

The hint given shows how to make a substitution to get it in terms of sine, and it looks like you did that correctly, but what is the value of a?

OpenStudy (poofypenguin):

I was hoping you could tell me...

OpenStudy (anonymous):

:-) Let's look at the substitution made cos(7x) = a*sin(x-3π/2) Why do you suppose that works?

OpenStudy (poofypenguin):

it could be derived from some trig identities that i'm unaware, possibly something like the double angle theorem?

OpenStudy (anonymous):

*(oops, meant cos(7x) = a*sin(7(x-3π/2)) as the substitution) Yes, it has to do that sine and cosine differ by 90º

OpenStudy (poofypenguin):

So am i supposed to solve for a first?

OpenStudy (anonymous):

Yes. Pick some other value of x and compare cos(7x) with sin(7(x-3π/2)).

OpenStudy (poofypenguin):

I set x = 1 and both cos(7x) and sin(7(x-3π/2)) came out the same...doesn't that imply that a = 1?

OpenStudy (anonymous):

Are you sure they were exactly the same?

OpenStudy (poofypenguin):

Oh! Whoops i must have typed it into my calculator wrong! They are opposites...so does that mean that a=-1?

OpenStudy (anonymous):

Yes. :-)

OpenStudy (anonymous):

So what's the limit?

OpenStudy (poofypenguin):

The limit is -7!

OpenStudy (anonymous):

You got it!

OpenStudy (poofypenguin):

Thanks so much for your help! :D

OpenStudy (anonymous):

Do some more research on L'Hopital's rule and try this problem using that method. I think you'll like it.

OpenStudy (poofypenguin):

Is there any good resources that you'd recommend for it?

OpenStudy (anonymous):

Wikipedia has a good article, but it might be a little too dense. Try maybe Paul's Online Math Notes http://tutorial.math.lamar.edu/Classes/CalcI/LHospitalsRule.aspx It's the go-to place for most good notes and examples.

OpenStudy (anonymous):

I'll show you how it works on the problem you had here: \[\large \lim_{x \rightarrow 3π/2} \frac{cos(7x)}{x-3π/2} = \lim_{x \rightarrow 3π/2} \frac{\frac{d}{dx}cos(7x)}{\frac{d}{dx}(x-3π/2)}\] \[\large \rightarrow \lim_{x \rightarrow 3π/2} \frac{-7sin(7x)}{1} = -7.\]

OpenStudy (anonymous):

Better, eh?

OpenStudy (poofypenguin):

Yeah much better! I will check out that site for sure! Thanks again! :D

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