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f(x)=xtothefifth and g(x)=-2-3xsqaured which is f(g(x))
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(-2-3xsquared)tothefifth
you take g(x) to be your x and therefore insert -2-3x^2 into f(x)
and then you get what @wio just wrote :D
But you still may have to expand it.
when x=t, \[g(t)=-2-3t^2\] Then \[f(g(t)=(-2-3t^2)^4\]
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no, why should you expand it if you already have the simplified version? I mean it depends on what they want but I think it would be pointless to expand to the power of 5 if you already have the expression simplified.
f(g(t))=(−2−3t2)^5, not 4
@Rimplestorck my bad...should be \[f(g(t))=(-2-3t^2)^5\]
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