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Mathematics 7 Online
OpenStudy (anonymous):

pleases guys i need a help with this: find the gradient of the tangent to the following curve at the point where y=-2. y=x^2-x-6

OpenStudy (anonymous):

calculate the 1st derivative, do you know how to do that?

OpenStudy (anonymous):

at y=-2, you should have two x values... and therefore two answers.

OpenStudy (anonymous):

the first derivative y'=2x-1 right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

now find the x values that correspond with y=-2.

OpenStudy (anonymous):

then plug those x values into your derivative

OpenStudy (anonymous):

i found two values of x can we have two tangents at the same point?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

but it's not the same point, it's just the same value of y

OpenStudy (anonymous):

so it is logical that there are two x values

OpenStudy (anonymous):

of course not.... there is only one tangent line at EACH point. but you have two points...

OpenStudy (anonymous):

did you solve it?

OpenStudy (anonymous):

two points having the same why value?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

they have the sam y value, which is -2 and have different x values

OpenStudy (anonymous):

i found two gradients, m1=3,512 and m2=-4,124

OpenStudy (anonymous):

so the two answers are correct?

OpenStudy (anonymous):

i don't know about the answers, but yes, there should be 2 gradients

OpenStudy (anonymous):

thank u o much guys i found the aswers but i ws not sure about getting two gradient thank u all

OpenStudy (anonymous):

your m1 and m2 are incorrect.... you should get \(\large m_1=\sqrt{17} \) for one of them.

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