pleases guys i need a help with this: find the gradient of the tangent to the following curve at the point where y=-2. y=x^2-x-6
calculate the 1st derivative, do you know how to do that?
at y=-2, you should have two x values... and therefore two answers.
the first derivative y'=2x-1 right?
yes
now find the x values that correspond with y=-2.
then plug those x values into your derivative
i found two values of x can we have two tangents at the same point?
no
but it's not the same point, it's just the same value of y
so it is logical that there are two x values
of course not.... there is only one tangent line at EACH point. but you have two points...
did you solve it?
two points having the same why value?
yes
they have the sam y value, which is -2 and have different x values
i found two gradients, m1=3,512 and m2=-4,124
so the two answers are correct?
i don't know about the answers, but yes, there should be 2 gradients
thank u o much guys i found the aswers but i ws not sure about getting two gradient thank u all
your m1 and m2 are incorrect.... you should get \(\large m_1=\sqrt{17} \) for one of them.
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