Question

if a+b is not equal to 0 and a-b is not equal to 0 then (a^2-b^2)/(a^2+2ab+b^2) - (ab-a^2)/(a^2-b^2) is equal to what?

Answer 1

factorize it first.

Answer 2

agreed...^^^

Answer 3

um.... i got ab(a-b)/ ab(a+2+b) - a(b-a)/ ab(a-b)

Answer 4

\(\large \frac{a^2-b^2}{a^2+2ab+b^2 } - \frac{ab-a^2}{a^2-b^2}\)

= \(\large \frac{\cancel{(a+b)}(a-b)}{\cancel{(a+b)}(a+b) } - \frac{a\cancel{(b-a)}^{-1}}{(a+b)\cancel{(a-b)}}\)
= \(\large \frac{a-b}{a+b}+\frac{a}{a+b} \)
= \(\large \frac{2a-b}{a+b} \)

Answer 5

oh thanks :)

Answer 6

yw...:)