Question

Find the axis of symmetry of the graph of the function.

f(x) = 2x2 - 16x + 27

A. x = -3

B. x = 4

C. x = -5

D. x = 6

Answer 1

i keep getting an answer thats not one of the choices :( please help..

Answer 2

-b/2a
x==4

Answer 3

howd u find that answer?

Answer 4

i just found the vertex and the equation is -b/2a
so its -(-16) / 2(2) = 4

Answer 5

but what happens to the 27?

Answer 6

If you complete the square, you can find the low point of the parabola. It's a low point since the parabola opens upwards.

Answer 7

27 is just an intercept it is not needed

Answer 8

oohhhok, so the axis of symmetry would be 4?

Answer 9

2x2 - 16x + 27 = 2(x-4)^2 - 5

Answer 10

So, low point at (4, -5) and the parabola opens up on either side symmetrically. So axis of symmetry at x=4.

Answer 11

oohhok! thankyou!!