Find the axis of symmetry of the graph of the function.

f(x) = 2x2 - 16x + 27

A. x = -3

B. x = 4

C. x = -5

D. x = 6

Question

Find the axis of symmetry of the graph of the function.

f(x) = 2x2 - 16x + 27

A. x = -3

B.  x = 4

C. x = -5

D. x = 6

anonymous · Answer

i keep getting an answer thats not one of the choices :( please help..

anonymous · Answer

-b/2a 
x==4

anonymous · Answer

howd u find that answer?

anonymous · Answer

i just found the vertex and the equation is -b/2a
so its -(-16) / 2(2) = 4

anonymous · Answer

but what happens to the 27?

anonymous · Answer

If you complete the square, you can find the low point of the parabola.  It's a low point since the parabola opens upwards.

anonymous · Answer

27 is just an intercept it is not needed

anonymous · Answer

oohhhok, so the axis of symmetry would be 4?

anonymous · Answer

2x2 - 16x + 27 = 2(x-4)^2 - 5

anonymous · Answer

So, low point at (4, -5) and the parabola opens up on either side symmetrically.  So axis of symmetry at x=4.

anonymous · Answer

oohhok! thankyou!!