Question

did i work this our correctly?
solve; r=2 thirds*t+v, for t.
-v -v
r-v=two thirds*t (multiplied be three)
*3 *3
r-v*3=2t (divided be two)
r-v*3(over a fraction bar) 2 (under the fration bar) =t

PLZ HELP! I need to get a 100 on this!

Answer 1

solve; \[r=\frac{ 2 }{ 3 }t+v\], for t.

Answer 2

r = 2 t/3 + v
2 t/3 = r - v
=> t = (3/2 ) ( r -v)

Answer 3

i got \[t=\frac{ r-v*3 }{ 2 }\] when i was compleatly done.

Answer 4

You need the bracket:
t = 3 ( r -v) /2

Answer 5

she never taught us that, tho..

Answer 6

the way i typed it is how we end........(me confused)

Answer 7

@Chlorophyll , does it mean the same thing??? what u put and what i put?

Answer 8

@TuringTest @Callisto do u think u can help? did i work this correctly?

Answer 9

NO, they're different!

Answer 10

OMG! How?!

Answer 11

t = 3 ( r -v) /2
= ( 3r - 3v ) /2

Your answer:
t = ( r - 3v} /2

Answer 12

why multiply v and r by three?????! i dont get it!

Answer 13

r = 2 t/3 + v
2 t/3 = r - v
Multiply both sides for 3/2 :

Answer 14

Your post " r=2 thirds*t+v "
r = 2 t/3 + v
In case: r = 2 thirds ( t + v), then the result is different!

Answer 15

dont mind the rectangle or the line over to the side. i was messeing around a bit..