Question

the question i need help in is the picture in the comments

please help.

Answer 1

(a + b/c) (d + e/f) = [(ac + b)/c] [(df + e)/f]

Answer 2

so whic one is the awnser ?

Answer 3

The answer is contained in my reply. You are supposed to reason to the answer through hints and helps that we tutors provide. We are not allowed to just give answers. We are supposed to help you do your own work, not do your work for you.

Answer 4

With the formula I gave you, you should be able to at least start seeing which of the selections apply. You can immediately start eliminating at least one of the selections.

Answer 5

well that confusing so i am not sure whats the answer is

Answer 6

All right, if you are confused, what exactly is it that you are confused about? To start, do you understand the formula I gave you?

Answer 7

the whole thing! they are just letters and i am not sure to solve the formula
i just need help

Answer 8

In the factor (a + b/c), do you see that "a" is a whole number and that "b/c" is a fraction?

Answer 9

ok

Answer 10

And if we allow a + b/c = (ac + b)/c, what did we do to "a". It is no longer by itself. It has been multiplied by "c", then added to b, and the whole thing is a numerator over "c". We allowed certain operations on "a" that associated it to "c".

Answer 11

"a + b/c" is a whole number plus a fraction. What is "(ac + b)/c" ? Is it a fraction?

Answer 12

yes

Answer 13

Yes, you're right, it is a fraction and given that "a" is a whole number, "(ac + b)/c" is a particular type of fraction. Hint: the terminology as to what "(ac + b)/c" is is contained in the 4 selections in your question.

Answer 14

so the awnser is C?

Answer 15

In your problem statement, 5 + 7/9 is a mixed number. It fits the format of "a + b/c" which we "changed". Follow the steps of how I changed "a + b/c" and you will have your answer. I can't tell you any more than that without just giving you the answer.

Answer 16

52/9

Answer 17

?

Answer 18

I can't help you any further. Good luck to you.

Answer 19

what ever you where no help at all

Answer 20

can some one help me?