Question

Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π

f(x) = 4 cos^2(x) - 3

Answer 1

well you have

\[4\cos^2(x) - 3 = 0\]

or

\[4\cos^2(x) = 3\]

just keep solving...

Answer 2

cos(x)= √3/2

Answer 3

answers are π/6, 11π/6 ?

Answer 4

I think you will find there are 4 zeros.... remember taking the square root means plus and minus root 3

Answer 5

okay, π/6, 5π/6, 7π/6, 11π/6

Answer 6

looks better... well done