Ask your own question, for FREE!
Chemistry 10 Online
OpenStudy (anonymous):

HELP! >__< seems like an impossible problem... If you make a solution from 100.0g of unknown solute and 1000mL of water and find that it's boiling point is 1.024 degree C higher then that of pure water, what can you conclude about it's molecular weight? so.. Kbp for water is 0.512

OpenStudy (aaronq):

this is a colligative property question, boiling point elevation, in which amount of solute added affects the temperature at which the solvent will boil at due to obstruction of the solvent particles by the solute as they try to escape the liquid phase and evaporate. use: \[\Delta T = imK _{bp}\] i = van't hoff factor m=molality

OpenStudy (aaronq):

remember that molality= moles of solute/ Kg of solvent and moles=mass/molecular weight so the equation you're left with is \[\Delta T = i (mass/MW/Kg solvent) K _{bp}\] use some algebra and isolate MW

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!