Question

Convert to a heavyside function:

h(t):
1, pi==2pi I'm still have some problems trying to convert a step function into a heavyside function. I can do the LHS laplace transform but I can't get any further unless I convert g(t)

Answer 1

how does this look like?
\[\huge f(x) = \cases{1 \qquad \pi \le t \le 2\pi \\\\ 0 < \pi \quad \text & \quad t \ge 2\pi}\]
??

Answer 2

\[\huge f(x) = \cases{1 \qquad \pi \le t \le 2\pi \\\\ 0 \qquad 0 \le t< \pi \quad \text & \quad t \ge 2\pi}\]

is that how your question looks like?

Answer 3

that second part doesn't seem to make sense...

Answer 4

yeah, except for 1 pi=<t < 2pi

Answer 5

can you click that draw button and draw how the question actually looks like?

Answer 6

I'll take a picture, I can't seem to get the draw function to work properly for me.

Answer 7

It's the one in the center.

Answer 8

something like H(t-pi) - H(t-2pi) you mean?

Answer 9

yeah, I don't really understand how to convert a step function into that format.

Answer 10

Heaviside steps up to one when t=0, shift it to t=pi (that's the first term)
Now make it drop back to zero: subtract a Heaviside that's been time shifted to 2pi

Answer 11

hmm I see... I kind of understand now.

Answer 12

Paul's Notes goes over it... it's pretty simple really:)
http://tutorial.math.lamar.edu/Classes/DE/StepFunctions.aspx
is this for diff. eq.? or an engineering class?

Answer 13

It's for a differentials class :\

Answer 14

opps forgot to close this thread. I finally understand the heaviside format but instead of h(t-c) I used the u_c(t) format -> e^cs/s.