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Simplify the following quotient of complex numbers into the form a + bi. -9 + 8i/1
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Are you sure that's -9 + 8i/1? lol
:)
Because that'd just be what you already have.
\[\rm {blah \over 1}\]is always\[\rm blah\]
unless...
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unless the question is incomplete
Typo.
Simplify the following quotient of complex numbers into the form a + bi. -9 + 8i/1 + 2i
thought so
I am just busy with math homework and didn't realize it until I pulled the page back up. Sorry.
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Anyone know how to help?
yes, multiply and divide by conjugate of denominator, know what is conjugate ?
-9 + 8i/ 1 + 2i /-9 + 16i This is the first step I had.
conjugate of 1+2i = ?
3i
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conjugate of 1+2i is 1-2i
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