Question

Find to consecutive integers whose product is 168.

Answer 1

I just do not understand where to go from this equation: (x)(x+1)= 168, x^2 + x = 168

Answer 2

x^2+x=168
i think you should use the quadratic formula to solve this

Answer 3

how would the quadratic formula work if they have to be consecutive?

Answer 4

2n(2n+1)=168
n(2n+1)=84
2n^2+n-84=0
now it become a quadratic equation
solve it

Answer 5

OKay sorry I'm just really confused... what is 2n?

Answer 6

nothing...... i take here
2n and 2n+1
if u know apply here shri dhracharya formula

Answer 7

shri dhracharya formula?

Answer 8

the sum of a odd number and a even number impossible to get a even number, re-chek ur question...

Answer 9

x^2 + x - 168 = 0
can be used
and the roots are not integers

so there are no integers which satisfy this problem

Answer 10

oh hold on - its a product not a sum RadEn

Answer 11

oh, sorry... i was mistaken

Answer 12

no worries

Answer 13

i think theres a mistake in question

Answer 14

hmmm.. yea, i think so that

Answer 15

sure its not 156 ?
instead of 168

Answer 16

i said that because it would give a result of 12 and 13