Question

A car weighing 1600 kr travels at 90 km/h. The driver brakes and after 10s the car is standing still.

How far did the car travel after the driver began braking?

Answer 1

So far I've got an average deacceleration of 2,5m/s, but how do I get from there to the distance traveled?

Answer 2

u can use the suvat equations:

Answer 3

justwait

Answer 4

suvat equations:
v=u+at missing s
s=1/2(u+v)t missing a
s=ut+1/2at^2 missing v
s=vt-1/2at^2 missing u
v^2=u^2+2as missing t

Answer 5

s=distance
u=initial velocity (speed)
v=final speed
a=acceleration or deceleration
t=time

Answer 6

i don't understand what this part means "A car weighing 1600 kr "
is it the weight of the car?

Answer 7

yes, sorry that's a typo, it's supposed to be kg

Answer 8

thanks for your reply, I'll just stare at this for a while :)

Answer 9

so u have got
s=?
u=90 km/h in physics u have to convert units to m/s
v=0 m/s
a=?
t=10 s

Answer 10

can u calculate the u in m/s?

Answer 11

@math0101

Answer 12

u can calculate that then
choose one of the suvat equations

Answer 13

u will probably use this equatiion:
s=1/2(u+v)t

Answer 14

then substitute the values and then u have the distance travelled by the car

Answer 15

I've realized I need to look into this further so I'm looking through the chapter on constant acceleration now that I know what I need to know / understand. Thanks for your help :)

Answer 16

answer is 125 metres

Answer 17

it's ok
pleasure @math0101

Answer 18

u r right @rexparkar but u don't need to give answers like this but let others try first especially the ones who asked the question

Answer 19

ok

Answer 20

its a constant retardation problem