Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (3psilon):

Distance between two parallel lines 3x+y=12 and mx + 2y =4

OpenStudy (3psilon):

Wouldn't the slope of the second line have a slope of 3 also? It says the slope is 6 in my book

OpenStudy (anonymous):

Not 3 but -3

OpenStudy (amorfide):

parallel means it would have the same gradient perpendicular lines gradient would be the negative reciprocal

OpenStudy (amorfide):

yes it would be 3 also

OpenStudy (3psilon):

But why does it say "since they are parallel , m = 6" I'm confused

OpenStudy (anonymous):

Because you have a 2y in your equation.

OpenStudy (3psilon):

Wouldn't that make it y = 3/2x+2?

OpenStudy (3psilon):

Ohhh I see it now!

OpenStudy (radar):

Why wouldn't it be a -6 ??

OpenStudy (3psilon):

Yeah now that you mention it @radar I'm confused too 0_o

OpenStudy (radar):

And they want the perpendicular distance between these two parallel lines........right?

OpenStudy (3psilon):

Just the distance between?

OpenStudy (anonymous):

To start off, what do you need to obtain the distance?

OpenStudy (radar):

I believe the two equations can be resolved to: y=-3x + 12 and y=-3x + 2 these lines are parallel as they do have the same slope. But I don't know how to determine the distance between them. Maybe you determine a line that is perpendicular to one line and intersects at a point on the other. Good luck with it.

OpenStudy (3psilon):

D = Sqrt(10) @Chlorophyll ?

OpenStudy (anonymous):

Wow, that's fast! I haven't calculated at all, just express out my concept :P

OpenStudy (anonymous):

@3psilon However I'd like to see how do you come up with it, would you!

OpenStudy (3psilon):

Oh no it was in the book! lol

OpenStudy (anonymous):

You'd better roll up your sleeve now ;)

OpenStudy (3psilon):

How is 10/Sqrt(10) the same as sqrt(10)?

OpenStudy (anonymous):

Yep, my result is √10 units!

OpenStudy (anonymous):

Where do you get: 10/Sqrt(10) :0

OpenStudy (anonymous):

Anyway, 10/√10 = √10 * √10 / √10 = ....

OpenStudy (radar):

|dw:1350235279426:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Mari103: How to pop out like a Jacc In the box
46 minutes ago 0 Replies 0 Medals
Breathless: Spooky witch but cute
7 hours ago 3 Replies 0 Medals
Arriyanalol: help
7 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
10 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
10 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!