Distance between two parallel lines 3x+y=12 and mx + 2y =4
Wouldn't the slope of the second line have a slope of 3 also? It says the slope is 6 in my book
Not 3 but -3
parallel means it would have the same gradient perpendicular lines gradient would be the negative reciprocal
yes it would be 3 also
But why does it say "since they are parallel , m = 6" I'm confused
Because you have a 2y in your equation.
Wouldn't that make it y = 3/2x+2?
Ohhh I see it now!
Why wouldn't it be a -6 ??
Yeah now that you mention it @radar I'm confused too 0_o
And they want the perpendicular distance between these two parallel lines........right?
Just the distance between?
To start off, what do you need to obtain the distance?
I believe the two equations can be resolved to: y=-3x + 12 and y=-3x + 2 these lines are parallel as they do have the same slope. But I don't know how to determine the distance between them. Maybe you determine a line that is perpendicular to one line and intersects at a point on the other. Good luck with it.
D = Sqrt(10) @Chlorophyll ?
Wow, that's fast! I haven't calculated at all, just express out my concept :P
@3psilon However I'd like to see how do you come up with it, would you!
Oh no it was in the book! lol
You'd better roll up your sleeve now ;)
How is 10/Sqrt(10) the same as sqrt(10)?
Yep, my result is √10 units!
Where do you get: 10/Sqrt(10) :0
Anyway, 10/√10 = √10 * √10 / √10 = ....
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