How to calculate the total surface area of this shape?
you gotta give the shape....☺
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Sorry I meant cylinder
for the hemisphere 5 cm is the radius or diameter???
Its not written as its radius because in my book the question is to find the total surface area of the combined shape
ok try this......
for the cone surface area is \[\pi*r*l\] where r = 5 cm and l=12 cm and pi can be taken as 3.1416 or 22/7
for the cylinder surface area is \[2\pi*r*h\] where r = 5 cm and h = 10 cm and pi can be taken as 3.1416 or 22/7
for the hemisphere surface area is \[2\pi*r ^{2}\] where r = 5 cm
the sum of all three will give the total surface area of the given picture
So I have to calculate the curved surface area of each shape
yes because they are all joined together and in each case only the curved surface is exposed...
I got 660 cm squared but the answer in the book is 675 cm squared
let me check.....
I think the diameter is 5. So the radius would be 2.5.. :)
It will be 330
if we take radius as 2.5 the answer will be even smaller.....
I checked, the answer is 660 and not 675.....maybe there is a printing error in the book...☺
I think this question before and I think I got 675 not 660 but I don't remember
I will ask my teacher about this one then I will tell u tommorrow , OK?
OK :)
sure....check with your teacher....but as per the given dimensions it gives answer as 660
I asked my teacher and he got the answer 675. Hemisphere: \[2*3.14*5^{2} = 157 cm ^{2}\] Cylinder: \[2*3.14*5*10=314 cm\] Cone: \[3.14*5*13=204 cm\] Total surface area: 157+314+204= 375 cm squared
For the cone you gave slant height as 12 and your teacher has used the value 13.......that is the reason for him getting this answer.............!!!!!
NOO The slant height was not given but it was the vertical height
Excuse me
OK but no vertical line or indication was given that it was vertical height. Since it was written next to the slanting side, I took it as slant height....☺
Sorry for not showing it was a vertical height
no problem...☺......you got the right answer...that is important
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