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Mathematics 20 Online
OpenStudy (anonymous):

determine f^(2)(x) when f(x)=3sinx+cosx

OpenStudy (anonymous):

are you trying to find the second derivative?

OpenStudy (anonymous):

i guess so

OpenStudy (anonymous):

f'(x) = the derivative of 3sin(x) + the derivative of cos(x), can you do that?

OpenStudy (anonymous):

no i can not

OpenStudy (anonymous):

ok no problem, the derivative of sinx is cosx, you just need to remember that, and the derivative of 3 times sinx is just 3 times cosx, so the constant 3 just goes with it. The derivative of cosx is -sinx, again you just need to remember that, so the derivative of the whole thing is those two derivatives added together

OpenStudy (anonymous):

\[f'(x) = 3\cos(x) - \sin(x)\]

OpenStudy (anonymous):

but this is just the first derivative. To find the second derivative you repeat the process I explained above

OpenStudy (anonymous):

thanks so much!

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