Question

Solve. box your answer(s).
x^2(3x+1)=24x

Answer 1

3x^2 + x^2= 24x
4x^2=24x
thats the first two steps. Distribute the x^2 and combine like terms. Try to solve from there

Answer 2

okay thanks!

Answer 3

i got [3x ^{2}+x ^{2}-24x=0\]

Answer 4

so from here do i set each term equal to zero?

Answer 5

No u cant do that unless u have something like (x-3)(x+5)=0

Answer 6

so i factor it then set them equal to zero?

Answer 7

yeah u gotta factor out an x

Answer 8

okay!

Answer 9

do u figure this one out @daisy.paz

Answer 10

not exactly. i got to \[3x ^{2}+x ^{2}-24x=0\]

Answer 11

from here i don't know where to go.

Answer 12

3x^3 not 3x^2

Answer 13

true! thanks for catching the mistake

Answer 14

yeah! way to go man @surdawi where do we go from there tho?

Answer 15

factor an x

Answer 16

i feel like i should factor it and then set it to zero to get the answers

Answer 17

i think u should factor the x out. Then it will be in quadratic equation form

Answer 18

x(3x^2+x+24)=0

Answer 19

thats what i said

Answer 20

okay. where did you get positive 24?

Answer 21

-24 sry

Answer 22

ok and from there do i factor it?

Answer 23

is that [a ^{2}+b ^{2}=c ^{2}\]

Answer 24

hey @daisy.paz, jbovey doesnt want me to help you with this question

Answer 25

http://en.wikipedia.org/wiki/Quadratic_equation

Answer 26

then plug those numbers into quadratic equation

Answer 27

u get it?

Answer 28

not yet.

Answer 29

i have 9x^2+1x+24=0

Answer 30

is that righ or wrong? i don't know where to go from here?

Answer 31

no thats wrong. a=3 b=1 c=24 just plug those #'s into the quadratic equation. Read that link I posted for u

Answer 32

so its [3x ^{2}+x ^{2}+24=0\]

Answer 33

i mean 3x^2+x-24=0

Answer 34

Thats the form u need it in to calculate what a,b, and c equal. Once you know this plug it into the quadratic equation which is this.

Answer 35

c=-24 sry i keep forgetting its negative

Answer 36

okay

Answer 37

lemme kno when u calculate it and ill let u kno if its right

Answer 38

\[-1\pm \sqrt{288\div6}\]

Answer 39

the divide by 6 should be at the bottom

Answer 40

almost but it should be square root of 289 not 288. The square root of 289=17.
so Its 17/6

Answer 41

but the square root equals a decimal. so i think i am wrong

Answer 42

-1+or- (17/6)

Answer 43

ok

Answer 44

pretty complicated, but once u know what a,b, and c are it should be easy.

Answer 45

okay! thank you!

Answer 46

wouldn't it be -1/6

Answer 47

i would round 17/6 to 3. so you'll get two answers. -1+3=2 and -1-3=-4

Answer 48

just let ur teacher know u rounded

Answer 49

\[-\frac{ 1}{ 6 }\pm\frac{ 17}{ 6 }\]
\[-\frac{ 1}{ 6 }+\frac{ 17}{ 6 }=\frac{18}{6}=3\]
\[-\frac{ 1}{ 6 }-\frac{ 17}{ 6 }=\frac{16}{6}=\frac{ 8}{ 3 }\]
but still missing a value

Answer 50

oh yeah forgot to put -1/6. sorry bout that

Answer 51

jbovey do you want to tell her the 3rd solution?

Answer 52

im not exactly sure what that would be. You go ahead man, thanks for catching my mistake @surdawi

Answer 53

x(3x^2+x-24)=0
-3 and 8/3 are the solutions for (3x^2+x-24) "i did an error when calculating up there"
but x=0 is also a solution

Answer 54

\[-\frac{ 1 }{ 6 }+\frac{ 17 }{ 6 }=\frac{ 16 }{ 6 }=\frac{ 8 }{ 3 }\]
\[-\frac{ 1 }{ 6 }-\frac{ 17 }{ 6 }=-\frac{ 18 }{ 6 }=-3\]

Answer 55

okay thank you so much to both of you!