Question

A mass m1 = 5.5 kg rests on a frictionless table and connected by a massless string to another mass m2 = 4.6 kg. A force of magnitude F = 37.0 N pulls m1 to the left a distance d = 0.7 m.
What is the final speed of the two blocks?
How much work is done by the tension (in-between the blocks) on block m2?
What is the tension in the string?
What is the NET work done on m1?

Answer 1

Work = F*d = delta KE

since they presumably start at V=0
F*d = 1/2 * 5.5*V^2 + 1/2*4.6*V^2

calculate F*d and use it to solve for V

Answer 2

for the second and third parts

F*d - 1/2*5.5*V^2 = work done on the second block

You can use that to find the tension, since the distance is the same for both blocks, so:

(Force of tension in the string between m1 and m2)*d = F*d - 1/2*5.5*V^2

Answer 3

make sense?

Answer 4

yes thank you!