Question

Find y prime if y=(x^2+3x-5)(cube root(x)-1)

Answer 1

i would probably start by rewriting it (x^2+3x-5)(x-1)^(1/3)

Answer 2

Okay should i do the chain rule?

Answer 3

i did product rule

Answer 4

u got it?

Answer 5

I got

Answer 6

dont think thats correct

Answer 7

was the original problem (cuberoot(x)) - 1)

Answer 8

only the x is under the cube root?

Answer 9

Only the x under the cube root that where I get stuck

Answer 10

oh i did it \[\sqrt[3]{x-1}\]

so you might be right

Answer 11

I just couldnt decide whether or not to do the chain rule and what to do with the (-1) if I do

Answer 12

well this is a product rule

(x^2+3x-5) d/dx(cube root(x)-1) + (cube root(x)-1) d/dx(x^2+3x-5)

Answer 13

= (x^2+3x-5) 1/3 x^-2/3 + (x^1/3 - 1) (2x+3)

Answer 14

just algebra and reducing after this point

Answer 15

Okay thank you!