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Chemistry 7 Online
OpenStudy (anonymous):

How can you tell whether something is aqueous, solid, or a gas?

OpenStudy (anonymous):

Aqueous/solid you can tell by solubility rules Gases can be predicted by boiling point of the compounds

OpenStudy (anonymous):

@Sheng I have the solubility rules paper, but I don't understand how to use it. Do you mind helping me?

OpenStudy (anonymous):

^^ that is the chart.

OpenStudy (anonymous):

read my mind

OpenStudy (anonymous):

but anyways, you see the first part says soluble compounds contain that means these ions below are more likely to be mostly soluble (aq) and that's why they are classified here, exceptions to this (which makes them solid) are listed on the right columns. For example...if I had a compound AgBr and I'm trying to predict the solubility. I would search Br- on the chart and see that Ag is an exception to the solubility rules. Thus AgBr is a solid (s). The 2nd part of the chart is just a different type of representation, these ions are mainly insoluble, and the exceptions in the right columns are when these ions are soluble. For example...if I had a compound Ca(OH)2, I look up OH-, and see that Ca2+ is an exception, thus the compound is (aq).

OpenStudy (anonymous):

So say it was FeBr, it would be a aq solution? @Sheng

OpenStudy (anonymous):

Yep, but remember Fe being a transitional element has a few possible charges which is why you need to specific its charge in parenthesis would either be Fe(II)Br2 or...Fe(III)Br3

OpenStudy (anonymous):

What about the insoluble compounds section? @Sheng

OpenStudy (anonymous):

It's the same except this time the exceptions makes the compound soluble

OpenStudy (anonymous):

Can you give me an example? @Sheng

OpenStudy (anonymous):

i did Ca(OH)2 (look above) xD

OpenStudy (anonymous):

Oh haha :P Okay, so what if it was P(OH)? Then would it be a gas..? @Sheng

OpenStudy (anonymous):

again, be careful with your oxidation number, phosphorous usually has a +5, +3, or -3 charge, so here lets just go with +5 P(OH)5, and solubility rules can never predict whether it's a gas, only for (aq) or (s)

OpenStudy (anonymous):

Oh, so would this be a solid? @Sheng

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

Are they always on the chart? Like, what if you had C+O=> 2CO?

OpenStudy (anonymous):

@Sheng

OpenStudy (anonymous):

I meant 2C+O2=> 2CO @Sheng

OpenStudy (anonymous):

you mean, C+O2 --> CO2 and no not everything will be on the chart, the chart is only for predicting compounds that deionizes here you are given no compounds, but rather a synthesis reaction involving carbon and oxygen

OpenStudy (anonymous):

So it's just a gas?

OpenStudy (anonymous):

@Sheng

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay, so what if you have Na3N? Would it be aqueous because it's a nonmetal and a metal? @Sheng

OpenStudy (anonymous):

usually when a non-metal bonds with a metal it produces a salt, so this would be most likely (aq), but I dont think they'll ask you to predict the phases in this type of problems

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