Question

Need some help with l'hopitals rule

Answer 1

Oh god I love L'hopital's rule.

Answer 2

Let's be best friends.

Answer 3

\[\frac{ lnx }{x }\]

Answer 4

x->0+

Answer 5

I love it more than he does

Answer 6

lol

Answer 7

infinity!

Answer 8

such a pain

Answer 9

is the answer

Answer 10

-inf

Answer 11

wait does ln function approach 0 from the negative side?

Answer 12

this is my problem though,

Answer 13

0+

Answer 14

1/x/1 = 1/x, x_>0+, should be +infinity

Answer 15

let's see what smooth has to say

Answer 16

Okay, so first you have to show that the limit is of indeterminate form. Is it something like \(\Large \frac{0}{0}, \frac{\infty}{\infty}, \frac{-\infty}{-\infty}\)
If it is, then you can use L'hopitals.

Answer 17

or 0^0, or 1^infinity, etc

Answer 18

i think there are 7 indeterminate forms

Answer 19

this is -inf/0

Answer 20

so i cant use lopitals?

Answer 21

Right. No l'hopital's in this case.
Try rewriting as \(ln(x)*x^{-1}\)
and then use product rule.

Answer 22

someone should put me back into calc 1