Question

An insulator in the shape of a spherical shell is shown in cross-section above. The insulator is defined by an inner radius a = 4.0 cm and an outer radius b = 6.0 cm and carries a total charge of Q = + 9.0 μC (1 μC = 10-6 C). (You may assume that the charge is distributed uniformly throughout the volume of the insulator).
What is Ey, the y-component of the electric field at point P which is located at (x,y) = (0, -5.0 cm) as shown in the diagram?

Answer 1

Use Gauss' Law... find Q enclosed by (Vinside/Vtotal)Qtotal

Answer 2

i got the row = 0.01415

Answer 3

?

Answer 4

row?

Answer 5

density

Answer 6

rho.
could be... I didn't do it that way... you divided Q by (4pi/3 )*(.06^3 + .04^3 ) ?

Answer 7

extra steps...

Answer 8

ok so by your way how would i get Ey

Answer 9

E*A = (Q/epsilon) *(5^3-4^3)/(6^3-4^3)

Answer 10

where A is the area of a sphere radius .05 m

Answer 11

so divide the A to the right side

Answer 12

yep

Answer 13

ok let me try it

Answer 14

kQ*.401 / .05^2

Answer 15

so what is the final equation

Answer 16

kQ*.401 / .05^2

Answer 17

-13E6 N/C j

Answer 18

get it?

Answer 19

thank you so much

Answer 20

No problem. Thanks for the medal.

Answer 21

you welcome