Given Quadrilateral ABCD

Find AB:

Question

Given Quadrilateral ABCD

Find AB:

darkprince14 · Answer

attachment

lgbasallote · Answer

are there any right angles there?

darkprince14 · Answer

angle A & D are right angles..

lgbasallote · Answer

are you familiar with transversals?

darkprince14 · Answer

sort of..but this problem have to be solved using the Laws of Sine and Cosine...

lgbasallote · Answer

bummer

darkprince14 · Answer

it's the last question on our exam earlier... the answer i got was$$\frac{ \sqrt{91} }{ 2 }$$ though i don't know if it's the right one...

darkprince14 · Answer

LOL XD

anonymous · Answer

I'm getting the same answer $$\frac{ \sqrt{91} }{2}$$
If you draw a line from B straight down (call it point E where it intersects DC), you can get the length of BE with 3*sin(30) = 3/2.  That is the same height of AD. Using AD and BD, you can use the pythagorean theorem to solve for AB. $$\sqrt{5^{2}-(\frac{ 3 }{ 2 })^2}=\frac{ \sqrt{91} }{ 2 }$$

darkprince14 · Answer

@Sacrelicious i also solved it like that...i just doubted my answer since a point costs a percent in the final grade...