Question

The length of a rectangle is 3cm more than twice its width. Find the largest possible width if the perimeter is at most 66cm. use an inequality to solve.

Answer 1

So where are you stuck? How did you set up the equation for perimeter?

Answer 2

i just don't get it

Answer 3

can you walk me through it?
I will give you best response

Answer 4

thanks molly :) you will be getting best response

Answer 5

Well, here's what we know. Perimeter = 2 * length + 2* height.

And L = 2*W + 3
And of course, P < = 66.

Answer 6

ok

Answer 7

so what next?

Answer 8

So, just plugging the 2W+3 equivalent into the formula for perimeter we get

P = 2*(2*W + 3) + 2*W must be less than or equal to 66.

Answer 9

so let y represent the length and x represent width. y=2x+3
Perimeter=2x+2y
Substitute in 2x+3 for y (P=2x+2(2x+3))
So now, P=6x+6
Plug in 66 for p and make it an inequality
66\[66\ge6x+6\]
then you would sovlve and get x=10

Answer 10

thanks :)

Answer 11

sorry
\[x \le10\]