Question

a 400 g bead slides on a curved frictionless wire, starting from rest at point a. find the speed of the bead at point b and point c.

Answer 1

attempt to the solution;
m = 400 g = 0.4 kg
A to B
(1/2)(0.4)(0) +(0.4)(9.8)(5)=(1/2)(0.4)(V_B^2)+(0.4)(9.8)(0)
V_B = 9.9 m/s ??

B to C
(1/2)(0.4)(9.9^2)+0=(1/2)(0.4)(V_C^2)+(0.4)(9.8)(2)
V_C = 7.67 m/s ??

Answer 2

@zzr0ck3r @heedcom

Answer 3

@AbhimanyuPudi

Answer 4

I did not check the calculation part but the approach is absolutely right...conservation of energy

Answer 5

thanks again! ..:)

Answer 6

welcome : )