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Mathematics 13 Online
OpenStudy (anonymous):

Can anyone help me with the derivative of: y=x^11 e^x

OpenStudy (anonymous):

\[y=x ^{11}e ^{x}\] Much easier to look at.

OpenStudy (mimi_x3):

do you know the product rule

OpenStudy (anonymous):

Yeah, I somehow worked out the problem by myself. Just want to make sure if I got it right or not.

OpenStudy (mimi_x3):

well tell me what you got :)

OpenStudy (anonymous):

I look really ridiculous, but: \[11x ^{10}e ^{x}+x ^{11}e ^{x}\] Here you go.

OpenStudy (mimi_x3):

looks right to me

OpenStudy (anonymous):

hm....ok, if you say so. I just don't feel right somehow. It look too long and weird.

OpenStudy (mimi_x3):

It's right! \(u=x^{11} => u' = 11x^{10}\) \(v=e^{x} => v' = e^{x}\) \(=> 11x^{10}*e^{x}+ x^{11}e^{x}\)

OpenStudy (mimi_x3):

You can also write it like: \(e^{x} (11x^{10}+x^{11})\) if it looks too "weird" :)

OpenStudy (anonymous):

ok, thanks :D

OpenStudy (calculusfunctions):

You could also factor the \[x ^{10}\]and express the derivative as\[\frac{ dy }{ dx }=x ^{10}e ^{x}(11+x)\]

OpenStudy (anonymous):

Cool, thanks

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