solve the inequality x(x-1)(x+2)>0
do you know how to start?
you can do this by drawing a graph
yes..what i know is that x>0 , x>1 , x>-2 what's the domain???
it should be x<0
or by considering the value of the fundtion between critical points these are the zeros of the function 0, 1 , -2
-2<x<0 or x>1
x is not equal to 0, 1 and -2. Its value lies in the intervals (2,0)U(1,infinity)
i get the (1,infinty) part...but i dont get why did we take (2,0)???
@akhilnkumar - i didn't say x was equal tp 0,1 or -2
Try puting the value as, say -1 or anything between 0 and -2
Sorry about my previous post the intervals are (-2,0)U(1,infinity)
yes - build a table and consider the values of function in the intervals x < -2, -2=< x < 0, 0 =<x < 1 , x >= 1
heres the graph http://www.wolframalpha.com/input/?i=x%28x%2B1%29%28x%2B2%29+%3D+0
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