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Mathematics 16 Online
OpenStudy (anonymous):

solve the inequality x(x-1)(x+2)>0

OpenStudy (anonymous):

do you know how to start?

OpenStudy (cwrw238):

you can do this by drawing a graph

OpenStudy (anonymous):

yes..what i know is that x>0 , x>1 , x>-2 what's the domain???

OpenStudy (anonymous):

it should be x<0

OpenStudy (cwrw238):

or by considering the value of the fundtion between critical points these are the zeros of the function 0, 1 , -2

OpenStudy (anonymous):

-2<x<0 or x>1

OpenStudy (anonymous):

x is not equal to 0, 1 and -2. Its value lies in the intervals (2,0)U(1,infinity)

OpenStudy (anonymous):

i get the (1,infinty) part...but i dont get why did we take (2,0)???

OpenStudy (cwrw238):

@akhilnkumar - i didn't say x was equal tp 0,1 or -2

OpenStudy (anonymous):

Try puting the value as, say -1 or anything between 0 and -2

OpenStudy (anonymous):

Sorry about my previous post the intervals are (-2,0)U(1,infinity)

OpenStudy (cwrw238):

yes - build a table and consider the values of function in the intervals x < -2, -2=< x < 0, 0 =<x < 1 , x >= 1

OpenStudy (cwrw238):

heres the graph http://www.wolframalpha.com/input/?i=x%28x%2B1%29%28x%2B2%29+%3D+0

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