I have a questions that doesn't appear to be an equation. Not sure how to solve. What is the solution of sq rt.(5x+1) The possible sol'n are x =0; x=16 and x=0; x=16; x=16 and x=1

Question

I have a questions that doesn't appear to be an equation.  Not sure how to solve.  What is the solution of sq rt.(5x+1)  The possible sol'n are x =0;  x=16 and x=0;  x=16;  x=16 and x=1

klimenkov · Answer

If you want to get a solution type an equation firstly.

anonymous · Answer

Shouldn't there be an equals sign somewhere in the initial equation of sqrt*x+) ?

anonymous · Answer

sorry sqrt(5x+1)

anonymous · Answer

there is no = sign  just the sq rt sign with 5x+1 under it   Can it not be solved unless there is an = sign.  Maybe something is missing.

anonymous · Answer

Maybe look higher up sometimes my math textbook says like for all of these equations solve when equal to five or something like that.

anonymous · Answer

I don't get what u r saying

anonymous · Answer

ahhh I think I know what they mean now I think the equation is in the form y=sqrt(5x+1) which means they want you to solve for when it crosses the x axis. See if that sounds like something you have/are doing in class.

anonymous · Answer

my lesson is solving sq rt and other radical equations

anonymous · Answer

Maybe it means which solution sets are possible....

anonymous · Answer

Some constraint....

anonymous · Answer

Unfortunately I cannot help you as a) I do not fully understand what you are asking and b) I have to go I have class in 15 minutes

anonymous · Answer

I would like to see wording of exact question...

anonymous · Answer

exact wording is:  What is the solution of sq. rt (5x+1)?

anonymous · Answer

The whole question....

anonymous · Answer

that is the whole question

anonymous · Answer

What about the solutions part?

anonymous · Answer

possbile answers are   x=0;  x=16 and x=0;  x=16; x=16 and x=1

phi · Answer

It might be a typo in the question.  
The answers you gave imply

sqrt(5x+1)= 1   or maybe sqrt(5x+1)= 9
are possible equations.

anonymous · Answer

What is the solution of sq. rt (5x+1)?
Possbile answers are   x=0;  x=16 and x=0;  x=16; x=16 and x=1

That's what it says?

anonymous · Answer

yea because if you solve for zeros you get
5x+1=0
5x=-1
x=-1/5

anonymous · Answer

exactly

anonymous · Answer

I tried solving for 0

anonymous · Answer

I was thinking it's a typo but wasn't sure.  Thought maybe I was missing something

anonymous · Answer

As far as I can tell you seem to be missing a crucial piece of this question somewhere.

phi · Answer

I would bet your are a victim here.  If you post a scan of the page, it might make it obvious to us...