the height 'h' meters of water in a harbour 't' hours after noon is depicted by:
h = 4+2sin(30t)
a boat can enter the harbour if the water is atleast 3 meters high. Find the times before midnight which the boat CAN'T enter the harbour.
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OpenStudy (anonymous):
now the minimum is 2, and the maximum is 6.
OpenStudy (anonymous):
and if it can't be in the harbour, it must be
4 + 2sin(30t) < 3
is this right??
OpenStudy (anonymous):
then i get
sin(30t) < -0.5
OpenStudy (anonymous):
but now how do I solve it??
hartnn (hartnn):
u want to know hoe to solve sin^-1 (-0.5) ?
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hartnn (hartnn):
what is sin^-1(0.5) = ?
OpenStudy (zugzwang):
After noon and before midnight means t goes from 0 to 12
OpenStudy (zugzwang):
It would be good first to find values of t for which sin(30t) = -0.5
OpenStudy (anonymous):
7, 11 :P
OpenStudy (zugzwang):
So, if t is from 0 to 7, is sin(30t) < -0.5 ?
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OpenStudy (anonymous):
no.
OpenStudy (zugzwang):
Then, from 0 to 7, the boat can't enter. How about from 7 to 11?