the height 'h' meters of water in a harbour 't' hours after noon is depicted by: h = 4+2sin(30t) a boat can enter the harbour if the water is atleast 3 meters high. Find the times before midnight which the boat CAN'T enter the harbour.
now the minimum is 2, and the maximum is 6.
and if it can't be in the harbour, it must be 4 + 2sin(30t) < 3 is this right??
then i get sin(30t) < -0.5
but now how do I solve it??
u want to know hoe to solve sin^-1 (-0.5) ?
what is sin^-1(0.5) = ?
After noon and before midnight means t goes from 0 to 12
It would be good first to find values of t for which sin(30t) = -0.5
7, 11 :P
So, if t is from 0 to 7, is sin(30t) < -0.5 ?
no.
Then, from 0 to 7, the boat can't enter. How about from 7 to 11?
ohhh, ok, got it. so 7<t<11
:)
lol thanks :)
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