A cannon launches a cannonball with an initial speed 210 m/s at a 70° angle from the horizontal. If the cannonball has a mass of 25 kg, how much work does it take to launch the cannonball to 1.985 kilometers?
1.985 km vertically? Just find the potential energy at that height.
For whihch u have to Find Time of flight........or is it like wat cliff said...is it vertical distance or Horizontal
Why those equations, @Yahoo! ? The force is the weight of the cannonball.
Vertical distance
1.985 is the maximum height
Yup...u r correct...@CliffSedge have nt thought that......
sorry P.E = mgh
I'm tempted to answer this question with "More work than the canon is capable of." @Yahoo! yes.
Lol...)
Naw, but seriously, considering significant figures, the max height is between 1980 and 2000 meters, so 1985 m is within the margin of error.
But, yeah, anyway Work = change in potential energy. Potential energy = mgh.
So would g almost always equal 9.8?
It has an average of 9.81 near sea-level on the Earth. It varies from place to place and decreases with height, but g=9.8 is always safe to use for these sorts of terrestrial problems.
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