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Mathematics 16 Online
OpenStudy (anonymous):

The number of distinct real roots of x^4-4x^3+12x^2+x-1=0

OpenStudy (anonymous):

Using Descartes’ Rule of Signs: 3 Sign Changes....So... 3 but the answer shuld be 2....hw?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

Gca? Try this site, it helps you understand how to do the problems you have trouble with! :D www.mathway.com

OpenStudy (anonymous):

You may have to sign up to see the steps though... otherwise you wont learn anything... you will just be recieving the answer.

OpenStudy (anonymous):

Don't forget the possible negative real roots as well.

OpenStudy (anonymous):

- ve roots f(-x) = x^4-4x^3+12x^2+x-1 + + + - - oh....1 - ve root

OpenStudy (anonymous):

Descartes' rule of signs tells you the possible numbers of positive real and negative real roots by looking at the sign changes in f(x) and f(-x). The sign changes in f(x) give possible number of positive real roots. The sign changes in f(-x) give possible number of negative real roots.

OpenStudy (anonymous):

There ya' go. So there could be 3 or 1 positive real roots, and there is 1 negative real roots.

OpenStudy (anonymous):

If there are only 2 real roots then that means that one of them is positive, the other negative, and the other two roots are imaginary.

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