The number of distinct real roots of x^4-4x^3+12x^2+x-1=0
Using Descartes’ Rule of Signs: 3 Sign Changes....So... 3 but the answer shuld be 2....hw?
@satellite73
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Don't forget the possible negative real roots as well.
- ve roots f(-x) = x^4-4x^3+12x^2+x-1 + + + - - oh....1 - ve root
Descartes' rule of signs tells you the possible numbers of positive real and negative real roots by looking at the sign changes in f(x) and f(-x). The sign changes in f(x) give possible number of positive real roots. The sign changes in f(-x) give possible number of negative real roots.
There ya' go. So there could be 3 or 1 positive real roots, and there is 1 negative real roots.
If there are only 2 real roots then that means that one of them is positive, the other negative, and the other two roots are imaginary.
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