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Can you explain how to solve this: 1+2+2^2+2^(-1) mod 9
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yes
the only question is what does \(2^{-1}\) mean in this context. it is clearly not \(\frac{1}{2}\) but rather the multiplicative inverse of 2
yes, this means inverse (but i don't really know what does it mean)
it means then number between 0 and 8 which, when multiplied by 2, will be 1 mod 9
you should be able to find it with no problem keep multiplying 2 by successive integers, when you get a number that leaves a remainder of 1 when divided by 9, that is your answer
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so, how do I approach to this kind of question? should I do a summation of all numbers like 1+2+2^2 or how?
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