Plz help me!!

Consider a water container, whose shape is the sphere with radius R. Suppose there is a small puncture at the bottom centre of this container and the water is leaking at a constant rate, k, that is, the volume of the water is decreasing at the constant rate k.
1. Explain why the rate of volume change is the surface area of the top of the water times the rate of the height change.
2. Find the rate of change of the height of the water in the container, when the height of water is .1/2R
3. Find the rate of change of the surface area of the top of the water when the height of w

Question

Plz help me!!

Consider a water container, whose shape is the sphere with radius R. Suppose there is a small puncture at the bottom centre of this container and the water is leaking at a constant rate, k, that is, the volume of the water is decreasing at the constant rate k.
1. Explain why the rate of volume change is the surface area of the top of the water times the rate of the height change.
2. Find the rate of change of the height of the water in the container, when the height of water is .1/2R
3. Find the rate of change of the surface area of the top of the water when the height of w

anonymous · Answer

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phi · Answer

for 1.   If you sketch it out, 
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