Question

If x is a positive integer then 2(x)³ =
8x
8x³
6x³
2x³
6x

Answer 1

Look at the problem and carefully consider what is happening. What is being raised to the third power.

Answer 2

the 2 is>

Answer 3

Which do you have here: \[2^3x, \space (2x)^3, \space 2^3x^3, \space or \space 2x^3\] Each one is doing something different.

Answer 4

the last one?

Answer 5

Correct, and what is being cubed?

Answer 6

I guess I should clarify, I assumed you identified the "last one" in my list as what operation was being done, and not to say that the "last one" in the answer list was correct.

Answer 7

That x is? or the 2 idk lol

Answer 8

The power is being applied to x only, because the parenthesis are only grouping the x, if you had (2x)^3, then the power would distribute in and apply to both the 2 and the x.

Answer 9

ok so how do i figure it out

Answer 10

If the power is only affecting the 'x', what would you get if you applied that power?

Answer 11

the same cause there is no number for x?

Answer 12

What if you had this instead? \[x*2^3\] How would you evaluate this?

Answer 13

And you are correct, because 'x' is unknown you would have the same answer.

Answer 14

What I had hoped to lead you to was this: \[2(x)^3 \rightarrow 2x^3\] because you would apply the power to the 'x' alone.

Answer 15

thank you for making it smiple

Answer 16

You're welcome