Question

Which of the following is the simplified form of (4x^3)/(9y^4)÷(8x^5)/(3y^2)

Answer 1

\[\frac{4x ^{3}}{9y ^{4}}\times \frac{3y ^{2}}{8x ^{5}}\]
The first part of simplification is to divide numerator and denominator by 4x^3. Can you do that?

Answer 2

do you know how divide two fractions ?

Answer 3

you need cooperat anything

ok ?

Answer 4

come on please i like to help you understanding

Answer 5

ok

so when you need divide two fractions you need multiplie first by second inversed

ok ?

how you have wrote there little up kropot72

ok ?

Answer 6

@kropot72 please end your work

Answer 7

When you divide numerator and denominator by 4x^3 you get the following:
\[\frac{3y ^{2}}{9y ^{4}\times 2x ^{2}}\]
Next divide numerator and denominator by3y^2 and get the following:
\[\frac{1}{3y ^{2}\times 2x ^{2}}=\frac{1}{6x ^{2}y ^{2}}\]