Question

how do you integrate -sin(x)^2

Answer 1

\[\int\limits_{}^{} -\sin ^{2}(x)\]

Answer 2

use\[\sin^2x=\frac12(1-\cos(2x))\]

Answer 3

double angle right?

Answer 4

once you substitute, you should get \[\int{\frac{cos(2x)}{2}-\frac{1}{2}dx}\]
which can be rewritten as
\[\int{\frac{cos(2x)}{2}dx-\int\frac{1}{2}dx}\]
Since an integral is a linear operator, you can separate it into two different integrals. The second integral is a straightforward one. The first one is a u-substitution. It's usually easier to choose your u to be what is 'inside' the function.

Remember that \[\int{cos(x)dx}=-sin(x)+c\]

Answer 5

alright, thats got it. Thanks