how many real roots does the polynomial 2x^5 + 8x - 7 have?
you know you have 5 solutions (total) because of the 5th power
yes but they are just possible roots--i need REAL roots
look at the graph and see how many times it crosses the x axis or bounces off the x axis
1 only see it cross in one place, means the other 4 are complex
it crosses at (0, -7)?
that is a y intercept and does not count. we are looking at the x intercepts
x=.79540551
but aren't x intercepts on a graph when x=0 (ie on y-axis)?
oh nevermind-- x intercepts are when y=0. right?
yes and I already identified one for you
hmm..i didnt get that--i got .7375?
i used the -b plus/minus the square root of b squared - 4ac all over 2a
can negative numbers be real roots?
can't use that because that is the quadratic formula and you can only use that with a 2nd power, you have a 5th power
then how do find an x-intercept?
have you been taught how to do synthetic division? only way to do this problem
yes i have been taught..but forget!!!
we answered the question, one real root
what equation do you divide by?
i knew the answer was one...i am just confused as to how we got one
in order to do synthetic division, don't we need 2 equtions?
no just a root and a polynomial what are your instructions because this one only has one real root because it cross the x axis in one place that means that the other 4 are complex solutions
the question is :how many real roots does the polynomial 2x^5 + 8x - 7 have? but i need to show work and be able to explain how i got my answer
well this one is not a nice one to do that with, you can state that it is one solution because it crosses the x axis at x=x=.79540551 since that is not a nice zero to work with (since it is an approximation) then it would not be a good candidate for synthetic division sorry gotta go
how do u get that answer
@precal
I looked at the graph and used my calculator to find the zero. But if my solution had been a nice whole number or fraction I would have shown you how to use syn division gotta go, good luck
okay thank you!
still dont get it... anyehlpe help!!?!?
**anyone
Hey I think I know what you guys are talking about :)) lol
can u explain to me???
@asherwood3
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