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Mathematics 15 Online
OpenStudy (strawberry17):

I do not understand about asymptotes and how to find them. Using these functions, (f(x) = 2x – 1 and g(x) = –2x – 1), can you please show me how to find the asymptote of each function and show your work so that I can understand?

OpenStudy (anonymous):

an Asymptote is a point in a curve which goes, theoretically straight to infinity in parallel with a straight line. In a form, it is a point in which, there is no visible curve or the difference in slope is so small, between points that it nears infinity.

OpenStudy (strawberry17):

That is a good explanation, but I still do not understand what the asymptote of one or both of the functions are. i have them graphed..

OpenStudy (strawberry17):

OpenStudy (strawberry17):

Are you still replying to my question?

OpenStudy (anonymous):

So, to get the asymptote, you have first create an inverse of the function. in this example, you are provided with the asymptotes already: so \[f(x) = 2x - 1\] and its mirror, g(x) are the asympototes. A linear slope does is already heading to an infinite direction, thus the asymptote has never occurred or is occurring infinitely. The two Asympote functions of g(x) and f(x) can be used to find out the curve.|dw:1350338178928:dw| which in this case will be Oblique as the result is not parallel to x or y. Unfortunately thats as far as my knowledge goes. I have yet to practice this level of algebra yet. Hopefully you'll find a better answer. Good luck getting one.

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